A piece of cork weighs 25g in air. It floats in water with 1/4 of the volume inside the water. What is the apparent weight of piece in water
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The buoyant force on cork = weight of the water displaced.
1/4 th of the cork is immersed i.e. it displaces a volume of water equal to 1/4 th of its own volume.
Hence, weight of water 1/4 th volume of cork would be equal to the weight of the floating cork.
Apparent weight = Real weight-buoyant force=1/4-1/4 =0
hope this was helpfull to you
MARK ME AS BRAINLIST
1/4 th of the cork is immersed i.e. it displaces a volume of water equal to 1/4 th of its own volume.
Hence, weight of water 1/4 th volume of cork would be equal to the weight of the floating cork.
Apparent weight = Real weight-buoyant force=1/4-1/4 =0
hope this was helpfull to you
MARK ME AS BRAINLIST
Answered by
14
The buoyant force on cork = weight of the water displaced.1/4th of the cork is immersed i.e. it displaces a volume of water equal to 1/4thof its own volume.Hence, weight of water 1/4th volume of cork would be equal to the weight of the floating cork.Apparent weight = Real weight-buoyant force=1/4-1/4 =0
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