A piece of gold aluminium alloy weighs 49N. When suspended from a spring balance and submerged in water it weighs 39.2N. What is the weight of gold in the alloy if the specific gravity of gold is 19.3 and that of aluminum is 2.5?
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The weight of the gold is 20.8 N
Explanation:
The mass of the water in 1 kg (9.8 N = m (9.8 m/s/s)),
Thus the volume of the water is 1000 ml.
5 = (Mau + Mal)/(Vau + Aal)
(Density = total mass to the total volume)
We know that:
19.2 = Mau/Vau and 2.5 = Mal/Val.
We have to find the volume. Therefore,
5Val + 5Vau = Mau + Mal
5(Mal/2.5) + 5(Mau/19.2) = Mau + Mal
Mal = 0.74 Mau
5 kg = M(au) + (1/.74)M(au)
=> M(au) = 2.13 kg
Weight of gold = 20.8 N
hence the weight of the gold is 20.8 N
Also learn more
A metal piece weighs 200 gf in air and 150 gf when completely immersed in water. (i) Calculate the relative density of the metal piece. (ii) How much will it weigh in a liquid of density 0.8 gcm-3?
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