a piece of gold o density 19.3g/cm3 weighs 10g in air and 9g in water what is the volume of cavity
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Explanation:
density of gold=19.3g/cm3
mass in air=10g
mass in water=9g
Actual volume of gold =10/19.3=0.518cm3
<br> Now, if V
be the weight of gold in water = weight of
volume of water <br>=10-9=V*1=1cc
<br> Volume of cavity =1-0.518=0.482cc
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