Question

A piece of gold weighs 350 gf in air and 300 gf when fully submerged in water. The density of water is 1 g/cm3. What is the volume of the gold piece?

Answer 1

Answer:

. Weight of the body air=350gf

. weight of the body in water=300gf

Loss of weight =350-300gf=50gf

upthrust of the body = loss in weight of the body = 50 gf

upthrust = V dg

50gf ×g = V × 1 gcm^-3 × (density of water = 1gcm^-3)

Volume of the body V= 50 cm ^3.