A piece of gold weighs 350gf in air and 300gf when fully submerged in water . The density of water is 1g/cm cube . What is the volume of the gold piece ?
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Explanation:
. Weight of the gold air=350gf
. weight of the gold in water=300gf
Loss of weight =350-300gf=50gf
upthrust of the gold = loss in weight of the gold = 50 gf
upthrust = V dg
50gf ×g = V × 1 gcm^-3 × (density of water = 1gcm^-3)
Volume of the gold V= 50 cm ^3.
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