Question

A piece of ice of mass 40 g is added to 200g of water at 50 ℃. Calculate the final temperature of water when all the ice has melted. Specific heat capacity of water =4200 J / kg K and specific latent heat of fusion of ice =336×10^3 J /kg

Answer 1

Let the final temperature is x deg.C
The heat absorbed or diffused is given by 
= q= mc
Heat absorbed by ice = Heat diffused by water
Heat absorbed by ice at latent heat = 336*1000*40/1000J= 13440J

Heat absorbed by ice when heating to x deg = q= mc
= 40/1000*4200*(x-0)
= 168x
Heat diffused by water = 200/1000*4200*(50-x)
= 840(50-x)
 = 168x + 13440 = 840(50-x)
x   = 28.3333

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