Question

A piece of ice of mass 40g is drop in 200g of water at 50degree celsius calculate final temperature of water after all ice has meltrx

Answer 1

Let the final temperature is x deg.C

The heat absorbed or diffused is given by Q=mc(theta)

What will happen here is that;

Ice will melt at 0 deg.C using its Specific latent heat of fusion

Then the melted ice at 0 deg will increase the temperature up to x deg C

The water will reduce temperature allowing ice to melt.

Therefore;

Heat absorbed by ice = Heat diffused by water

Heat absorbed by ice at latent heat = 336*1000*40/1000J= 13440J

Heat absorbed by ice when heating to x deg = mc(theta)

= 40/1000*4200*(x-0)

= 168x

Heat diffused by water = 200/1000*4200*(50-x)

= 840(50-x)

So;

168x + 13440 = 840(50-x)

x = 28.3333

So the final temperature is 28.333 deg.C