Question

a piece of ice of mass 60 gram is dropped into a 150 gram of water at 50 degrees celsius calculate the final temperature of water when all ice has melted semsem no it is lost in the to the surrounding
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Answer 1

Answer:

$12.85^{0}$C

Explanation:

specific heat capacity of water is 1 cal$gm^{-1}$ per degree

latent heat of fusion is 80 cal$gm^{-1}$

Let the final temperature be T

 ∴  60(80)+60(1)(T-0)=150(50-T)

=>  4800+60T=7500-150T

=> 210T=2700

=> T=$12.85^{0}$C

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