Question

A piece of ice of mass m gram is at minus 5 degree c at atmospheric pressure it is given for 20 rule of heat so that i starts melting finally when the water is mixture is in equilibrium it is found that one gram of ice has melted assuming there is no heat exchange in the process value of importance

Answer 1

Here is your answer Mate

The total heat given to the ice is utilized in two ways some heat us used as latent heat and rest used as specific heat to raise the temperature. Hence total heat,

Q=Latent heat + specific heat

Q=mL+mcΔT

Where m= mass of substance, L=latent heat,

c= specific heat capacity and = rise in temperature

step by step:

Step1: As given that heat capacity c=2100Jkg−1∘C

Latent heat =L=3.36×105Jkg−1

Now as heat is absorbed at 0∘C Therefore ΔT=0−(−5)=5∘C

Total heat given to ice Q=420J

Let the mass of the ice = m =?

Since the total heat given to the ice is utilized in two ways some heat is used as latent heat and rest is used as specific heat to raise the temperature. Hence total heat,

Q=Latent heat + specific heat

Q=mL+mcΔT …………….(1)

Where m= mass of substance, L=latent heat, c= specific heat capacity and = rise in temperature

Step2: substitute all the value in equation (1) and calculate m,

420=(1×3.36×105+m×2100×5)×10−3⇒m=8g

∴ The value of m is 8g

Thankyouu