Question

a piece of iron d=7.8×10^-3 and v=100 cm^3 is immersed in water calculate the weight of iron piece in air PLEASE ANS THIS AND I WILL GIVE YOU 20 POINT'S BUT IF YOU WROTE SOMETHING LIKE I DON'T KNOW OR etc i will report you with 6 accounts

Answer 1

Answer:

density of iron (Dr) = 7.8×10³ kg/m³

volume of iron piece(V) = 100cm³ = 10^(-4) m³

density of water (Dw) = 10³ kg/m³

(a) weight in air = Dr×V×g = 7.8×10³ × 10^(-4) ×10 = 7.8 N

(b) upthrust is the buoyant force exerted by water

   upthrust = Dw×V×g = 10³ × 10^(-4) ×10 = 1N

(c) apparent weight in water = weight in air - upthrust

                                        = 7.8N - 1N = 6.8N

Step-by-step explanation:

Answer 2

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