Question

A piece of iron has dimensions 3cm x 1.5cm x 6cm. If its mass is 205.2g, its relative density is

Answer 1

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Given :

• Length (L) = 3 cm
• Breadth (B) = 1.5 cm
• Height (H) = 6 cm
• Mass (m) = 205.2 g

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To Find :

• Relative Density

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Solution :

We have formula for Density :

$\large {\boxed{\sf{Density \: = \: \dfrac{Mass}{Volume}}}} \\ \\ \implies {\sf{Density \: = \: \dfrac{205.2}{3 \: \times \: 1.5 \: \times \:6}}} \\ \\ \implies {\sf{Density \: = \: \dfrac{205.2}{27}}} \\ \\ \implies {\sf{Density \: = \: 7.6 \: gcm^3}}$

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And for relative density is :

$\large{\boxed{\sf{Relative \: Density \: = \: \dfrac{Density \: of \: Substance}{Density \: of \: Water}}}} \\ \\ \implies {\sf{Relative \: Density \: = \: \dfrac{7.6}{1}}} \\ \\ \implies {\sf{Relative \: Density \: = \: 7.6}} \\ \\ {\underline{\sf{\therefore \: Relative \: Density \: is \: 7.6 \: gcm^3}}}$