Question

A piece of iron of density 7.8×10^3 kg/m^3 and volume 100cm^3 is totally immersed in water . calculate the weight of the iron piece .?​

Answer 1

Answer:

Apparent Weight = True weight – Upthrust = 7.8–1 = 6.8 N.

Answer 2

Given,

Density of Iron = 7.8×10³ kg/m³

Volume of iron piece = 100cm³ = 10⁻⁴m³

Density of water = 10³ kg/m³

To find,

The weight of Iron

Solution,

Density of Iron (Di) = 7.8×10³ kg/m³

Volume of iron piece (V) = 100cm³ = 10⁻⁴m³

Density of water (Dw) = 10³ kg/m³

weight of Iron (Mi )= ?

We can simply solve this numerical problem by using the following process:-

As we Know that,  

Mass= Density×Volume

Therefore,

Mi= Di×V

Mi= 7.8×10³ kg/m³×10⁻⁴ m³

Mi=7.8×10⁻⁷ Kg

Hence, the weight of Iron is 7.8×10⁻⁷ Kg