A piece of iron of density is 7.8 into 10 raise to the power 3 kg per metre cube and volume 100 cm cube is totally immersed in water. Calculate the weight of iron piece in air, upthrust and apparent weight in water
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Density of iron ρ = 7.8 x 103 kg/m3
Volume of iron piece V = 100 cm3 = 100 x 10−6 m3
Mass of the iron piece M = Vρ = 100 x 10−6 m3 x 7.8 x 103 kg/m3
= 0.78 kg
(i) Weight of the iron piece in air = Mg = 0.78 kg x 9.8 m/s2
= 7.644 kg. m /s2 = 7.644 N
(ii) Upthrust = Volume of the solid x density of water x g
= Vρwg
= 100 x 10−6 m3 x 1000 kg/m3 x 9.8 m/s2
= 0.98 N
(iii) Apparent weight of iron piece in water = Weight in air − upthrust
= 7.644 N − 0.98 N
= 6.664 N
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