Question

A piece of iron of mass 114 g, has a volume 15 cm3. Express the density of iron in
kg/m3? the answer is 7600 kg/ m^3​

Answer 1

Answer:

A

Explanation:

Correct option is

A

6.8N

Apparent weight of iron = Weight of iron in air - weight of iron in water

As we know , Density =

volume

mass

So mass of iron piece in air = (volume) (density) =(10

−4

)(7800)kg=0.78kg

Weight of iron piece in air=mg=7.8N

weight of iron piece in water = upthrust = Vρg = 10

−4

(1000)10N=1N

so apparent weight of the iron piece =7.8N−1N=6.8N

so option (A) is correct

Answer 2

Answer:

7.94 × 10^3 kg/m^3 is the answer

D = M/V

i.e. 119 × 10^-3 / 15 × 10^-6

I.e. its answer is 7.94 × 10^3 kg/m^3

Explanation: