A piece of iron of mass 156 g and density 7.8 g/3
floats on mercury of density
13.6 g/3
. What is the minimum force required to submerge it?(VOLUME IS NOT 100 CM^3)
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ρ
iron
=7.8×10
3
kg/m
3
ρ
Hg
=13.6×10
3
kg./m
3
Let volume of body=V
Weight of body = buoyant force
ρ
iron
Vg=ρ
Hg
V
′
g
7.8×10
3
×V=13.6×10
3
×V
′
V
′
=
13.6×10
3
7.8×10
3
V
′
=
136
78
V
V
′
=0.57V
Volume outside =V−V
′
V−0.57V
=0.43V
iron
=7.8×10
3
kg/m
3
ρ
Hg
=13.6×10
3
kg./m
3
Let volume of body=V
Weight of body = buoyant force
ρ
iron
Vg=ρ
Hg
V
′
g
7.8×10
3
×V=13.6×10
3
×V
′
V
′
=
13.6×10
3
7.8×10
3
V
′
=
136
78
V
V
′
=0.57V
Volume outside =V−V
′
V−0.57V
=0.43V
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