Question

A piece of iron of mass 156 g and density 7.8 g/3
floats on mercury of density
13.6 g/3
. What is the minimum force required to submerge it?
VOLUME IS NOT 100 CM CUBE

Answer 1

Explanation:

max force required is 77Newton

Answer 2

Explanation:

ρ

iron

=7.8×10

3

kg/m

3

ρ

Hg

=13.6×10

3

kg./m

3

Let volume of body=V

Weight of body = buoyant force

ρ

iron

Vg=ρ

Hg

V

′

g

7.8×10

3

×V=13.6×10

3

×V

′

V

′

=

13.6×10

3

7.8×10

3

V

′

=

136

78

V

V

′

=0.57V

Volume outside =V−V

′

V−0.57V

=0.43V