Physics, asked by mohitbhangale3324, 1 month ago

A piece of iron of mass 156 g and density 7.8 g/3
floats on mercury of density
13.6 g/3
. What is the minimum force required to submerge it?
VOLUME IS NOT 100 CM CUBE

Answers

Answered by vijaykrishnank2004
0

A piece of iron of mass 156 g and density 7.8 g/3

floats on mercury of density

13.6 g/3 .the minimum force required to submerge it is

12 N.

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Answered by Vermaaryan15
0
ρ
Hg

=13.6×10
3
kg./m
3

Let volume of body=V
Weight of body = buoyant force
ρ
iron

Vg=ρ
Hg

V

g
7.8×10
3
×V=13.6×10
3
×V


V

=
13.6×10
3

7.8×10
3



V

=
136
78

V
V

=0.57V
Volume outside =V−V


V−0.57V
=0.43V
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