A piece of iron of mass 156g and density 7.8gm per c.c floats on mercury of density 13.6gm per c.c what is the minimum force required to submerge it
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Answer ::-
Given :-
Density = 7.8 g/ cm^3
Volume = 100 cm^3
we know that ,
mass = density *volume
= 7.8 * 100 = 780 g
= 0.78 Kg
We know ,
weight = mg
= 0.78 * 10 = 7.8 N
It fully submerge in water .
Volume of displace water = density * volume of displace water = 1 * 100 = 100 g = 0.1 Kg
Weight of water = mg
= 0.1 * 10 = 1 N
Buoyant force = weight of displace fluid
Therefore ,
Buoyant force = 1 N
The weight of iron piece of water = weight in air - buoyant force = ( 7.8 - 1 ) N
= 6.8 N
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Explanation:
Final answer is 6.8 N
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