A piece of iron of mass 16g Is dropped ( at a temperature of 112.5⁰C ) into a cavity in a block of ice . So that it melts 2.5g ice . If the latent heat of fusion of ice is = 80cal/g the specific heat of iron is
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Answer:
135 J/kg K
Explanation:
Latent heat, L=Q/m
80×2.5=Q
Q=200 cal=836.8 J
Specific heat, s=ΔQ/mΔT
=836.8/16×10^-3×385.65
=52.3/385.65×10^-3
=135 J/kg K
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