Question

A piece of iron of mass 50g is to be heated from 20°C to 50°C. If specific heat of iron is 0.12 calg-1°C-1 then the heat re
is
(A) 1500 cal
(B) 6 cal
(C) 180 cal
(D) 60 cal​

Answer 1

Answer:

Explanation:

The correct answer is option(C).

Given: masss of water, m=1g,ΔT=(100−0)=100°C

And, the specific heat of water is, C=4.186Jg

−1

°C

−1

We know,  Heat gained, H=mCΔT=1×4.186×(100)=418.6J

or Heat gained = 100cal.

Answer 2

Answer:

C) 180 cal is answer dear friend