Question

A piece of iron of volume 30 cm cube has a mass of 234 g find the density of iron

Answer 1

Answer:

7.8 g/cm³

Explanation:

density = mass/volume

mass=234 g

volume=30 cm³

density=234/30

           =7.8 g/cm³

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Answer 2

Answer:

7.8g / $cm^{3}$is the required density of iron

Explanation:

Given , volume of  a piece of iron = 30$cm^{2}$

and mass of the iron = 234g  

And we know the formula of density = $\frac{mass}{ volume }$

⇒d =  $\frac{234}{30}$ = 7.8  g/$cm^{3}$  

or in kg /$m^{3}$ we get  ,

d = $\frac{78}{10}$ × $\frac{1000}{100 . 100 . 100}$ = 7800kg/$m^{2}$ .

Hence , the density of iron is 7.8 g / $cm^{3}$ .

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