Question

A piece of iron weighing 200 gm gives out 1000 calories of heat when it is cooled from 90°C to 10°C. When will be the specific heat of iron :​

Answer 1

Answer: The specific heat of iron will be $0.0625cal/g^0C$

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

$Q=m\times c\times \Delta T$

Q = Heat released = -1000 calories

m= mass of iron = 200 g

c = specific heat capacity of iron = ?

Initial temperature of iron = $T_i$ = 90.0°C

Final temperature of iron = $T_f$  = 10.0°C

Change in temperature ,$\Delta T=T_f-T_i=(10-90)^0C=-80^0C$

Putting in the values, we get:

$-1000cal=200\times c\times -80^0C$

$c=0.0625cal/g^0C$

The specific heat of iron will be $0.0625cal/g^0C$