A piece of iron weighs 275g; the piece floats with 5/9th of its volume immersed in mercury whose density is 13.6g/cm^3.Find the volume and density of the piece of iron
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Density of body = fraction of body in liquid x density of water
=( 1 — 1/3) x 1 = 2/3
Density of liquid = density of body / fraction of body in liquid
= 2 / 3 ÷ 1 / 4
= 2 x4 / 3 x 1
= 8 / 3
= 2.67
pls mark as brainlist answers
=( 1 — 1/3) x 1 = 2/3
Density of liquid = density of body / fraction of body in liquid
= 2 / 3 ÷ 1 / 4
= 2 x4 / 3 x 1
= 8 / 3
= 2.67
pls mark as brainlist answers
pari12345634:
pls mark me brainlist answer
Answered by
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Hlw mate here is your answer
A body floats on mercury with 1313 of its volume below the surface. Another liquid of density 110110 that of mercury is poured on top to cover the body completely. What is the fraction of cube now immersed.
pls mark me brainlist answer
A body floats on mercury with 1313 of its volume below the surface. Another liquid of density 110110 that of mercury is poured on top to cover the body completely. What is the fraction of cube now immersed.
pls mark me brainlist answer
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