a piece of iron weighs 44.5gf in air 39.5gf in water and 40.3gf in an oil find its relative density of iron
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Answered by
27
Relative density of a solid = weight of solid in air/ apparent loss of solid in air and in a liquid.
therfore the realtive density is 8.9.
therfore the realtive density is 8.9.
Answered by
44
Wa = weight of iron piece in air
Ww = weight of iron piece in water
normally relative density is calculated wrt water.
relative density of iron piece = Wa / (Wa - Ww)
= weight in air / Loss of weight in water
= 44.5 / (44.5 - 39.5) = 8.9
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if weight in oil is also known then you could calculate relative density of oil also.
relative density of oil = (Wa - Woil) / (Wa - Ww)
Ww = weight of iron piece in water
normally relative density is calculated wrt water.
relative density of iron piece = Wa / (Wa - Ww)
= weight in air / Loss of weight in water
= 44.5 / (44.5 - 39.5) = 8.9
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if weight in oil is also known then you could calculate relative density of oil also.
relative density of oil = (Wa - Woil) / (Wa - Ww)
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