Question

a piece of iron weighs 44.5gf in air, 39.5gf in water and 40.3gf in an oil. find the relative density of iron

Answer 1

Explanation:

Weight in air = 44.5 gf

Weight in water = 39.5 gf

Weight in oil = 40.3 gf

Let Relative Density of Iron = x

$x = \frac{wt. \: in \: air}{wt. \: in \: air - wt. \: in \: water}$

$= \frac{44.5}{44.5 - 39.5} = \frac{44.5}{5} = 8.9$

Hence , the relative density of iron is 8.9

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