Question

A piece of irregularly shaped metal weighs 300 N in air. When the metal is completely submerged in water, it weighs 232.5 N. Find the volume of metal.

Answer 1

Answer:

The answer will be 0.00675 m^3.

Explanation:

Taking

W1= 300 N

So the mass of metal is 300/9.8= 30.61 kg.

W2= 232.5N

Now upthrust= W1-W2= 67.5 N

Upthrust= volume of metal * Density of water *g

67.5= V * 1000 * 10

V= 0.00675 m^3.