Question

A piece of land 240 m long and 120 m wide has in its centre two roads of equal width 2.5 m One road is parallel to the length and the other is parallel to its width. Find the area of the roads.​

Answer 1

Answer:Area Covered by land Along the Length = 5*240 = 1200 Square Meter

Area Covered by land Along the Width = 5*120 = 600 Square Meter

Common Area in both land (where the road intersect) = Square with Side 2.5 meter = 2.5*2.5 = 6.25

Total Area of the Roads = 1200+600-6.25 = 1793.75

Step-by-step explanation:

Answer 2

The area of the road is very simple to calculate. We have to first find the area of both the roads. So we know that for both the roads, the breadth is 2.5m or 5/2m. Then the length is according to which road is parallel to which side of the piece of land. We find that road red is 600m^2 and road blue is 300m^2. We add them both and we get 900m^2. Then comes the tricky but easy part. As we can see, there is an area of common roads. The area is a square of side 2.5m each as it has the breadth and length of the roads. The area of the common piece of land is 6.25m^2. Now we just have to subtract them.

900 - 6.25 = 893.75

So the area of both the roads is 893.75m^2.

Mark my answer as the brainliest if found helpful as I had checked it twice. There is no mistake.