Physics, asked by srishti3feb7, 1 month ago

A piece of lead weighs 348g . If its volume is 30 cubic cm, what is the density of Lead​

Answers

Answered by Anonymous
13

Answer:

Given :-

  • A piece of lead weight 348 g.
  • The volume is 30 cm³.

To Find :-

  • What is the density of lead.

Formula Used :-

\clubsuit Density Formula :

\mapsto \sf\boxed{\bold{\pink{\rho =\: \dfrac{m}{v}}}}

where,

  • \sf \rho = Density
  • m = Mass
  • v = Volume

Solution :-

Given :

  • Mass = 348 g
  • Volume = 30 cm³

According to the question by using the formula we get,

\longrightarrow \bf \rho =\: \dfrac{m}{v}

\bigstar\: \: \sf\bold{\purple{Density =\: \dfrac{Mass}{Volume}}}\: \: \bigstar

\longrightarrow \sf Density =\: \dfrac{348}{30}

\longrightarrow \sf\bold{\red{Density =\: 11.6\: g/cm^3}}

{\small{\bold{\underline{\therefore\: The\: density\: of\: lead\: is\: 11.6\: g/cm^3\: .}}}}

Answered by CopyThat
45

Answer:

  • 11600 Kg/m³.

Explanation:

We have,

  • Mass (m) = 348 g
  • Volume (v) = 30 cm³

To find,

  • Density (ρ)

Solution,

> ρ = m/v

=> ρ = 348/30

∴ ρ = 11.6 g/cm³

_______________

> ρ = 11.6 g/cm³

=> ρ = 11.6 × 1000 Kg/m³

∴ ρ = 11600 Kg/m³

  • Hence, the density of lead is 11600 Kg/m³.
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