A piece of magnesium ribbon is dipped in CuSo4 solution after some Cu is found to get diposited on the ribbon what is the oxidation reaction takes place in here
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Answer:
Mg -> MgSo4
Explanation:
CuSO4 + Mg -> MgSO4 + Cu
now to calculate oxidation no. of Cu in CuSO4
x + (-2)=0
x=2
oxidation no. of Cu is 0 after reaction.
so Cu goes from +2 to 0 means it's reduced.
which means Mg is oxidised.
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