Question

A piece of marble tile weighs
100 g in air. If its density is 2.5 g/cc, what
will be its weight in water ?​

Answer 1

Answer:

weight in water=weight in air - upthrust

upthrust= density of water×g×volume of the tile

volume=mass/density=100/2.5

so upthrust=1×1000×100/2.5=40000dyne=0.4N

so weight in water=1-0.4=0.6N

hope it helps

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Answer 2

Answer:

weight in water = 60g

Explanation:

weight in air = 100g

density=2.5/cc ;volume=100g[2.5g/cc]=40cc

therefore,according to archemedes principal, when the piece is dipped in water , water of volume equal to the volume of the piece i.e 40 cc will be displaced the loss in the weight of the piece will be equal to the weight of displaced water 40g

;weight in water= 100g - 40g= 60g