a piece of marble tile weighs 100g in air. if its density is 2.5g/cc, what will be its weight in water
Answers
Answered by
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Explanation:
volume of marble = 100/2.5 = 40 cc
density of water is 1 g/cc
weight of water displaced =40*1 = 40 g
therefore buoyant force = 40 g
weight of marble in water = 100 - 40
= 60 g
Answered by
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Question :
a piece of marble tile weighs 100g in air. if its density is 2.5g/cc, what will be its weight in water?
Given :
weight in air = 100g.
Density = 2.5g/cc
Therefore, volume = 100g /(2.5g/cc)=40cc.
To find:
what will be it's weight in water?
Solution:
Therefore, according to Archemedes principle, when the piece is dipped in water water of volume equal to the volume of piece that is 40cc will be displaced .
The loss in the weight of piece will be equal to the weight of displaced water 40g.
Hence, weight in water = 100g - 40g = 60g
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