A piece of material of mass 100g is immersed in a measuring cylinder having water at a mark of 30ml. The water level rises to 38ml. Calculate the loss of weight of the piece of material.and also the buoyant force experienced by the piece of material.
ojaswi7:
thanks a lot for answering this too..................
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Answered by
37
Initial water mark on cylinder = 30ml
final water mark on cylinder = 38ml
volume of water displaced = 38 - 30 = 8ml
8ml = 8cm³
density of water = 1g/cm³
mass of water displaced = density*volume = 1 *8 = 8g = 0.008 kg
loss of weight = weight of water displaced = 0.008*9.8 N =0.0784 N
Loss of weight is same as the buoyant force.
So buoyant force is also 0.0784N
final water mark on cylinder = 38ml
volume of water displaced = 38 - 30 = 8ml
8ml = 8cm³
density of water = 1g/cm³
mass of water displaced = density*volume = 1 *8 = 8g = 0.008 kg
loss of weight = weight of water displaced = 0.008*9.8 N =0.0784 N
Loss of weight is same as the buoyant force.
So buoyant force is also 0.0784N
Yes!
Because the weight of water displaced= the weight of the substance immersed and not the loss of weiyth
*weight
"the weight of water displaced= the weight of the substance"
That holds only when the substance is floating on the water.
That holds only when the substance is floating on the water.
If it is immersed, then "the weight of water displaced= the weight loss of the substance"
seriously??????
oh..
yeah..seriously!! you can check it..
fine and thanks
see some example with iron ball and wooden object.
Answered by
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the loss of weight will be equal to the buoyant force so the answer is 0.0784N
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