Question

a piece of material x is given to us mass 40g with error 0.4g and its volume is 10cm^3 with error of 1 cm^3 . find density pls answer it :-( sparshu vo glt h i had already seen that answer on google ​

Answer 1

Answer:

4 ± 0.44 g/cm³.

Explanation:

Mass = 40 g

Error Mass (ΔM) = 0.4 g

Volume = 10 cm³

Error volume(ΔV) = 1 cm³

Then,

density = M/V

           = 40/10

          = 4

Now,

Relative error in measurement of density :

Δd/d = ΔM/M + ΔV/V

=> Δd/4 = 0.4/40 + 1/10

⇒ Δd = 0.44 g/cm³

Therefore, density of the material can be given as 4 ± 0.44 g/cm³.

Hope it helps!

Answer 2

Answer:

4±o.8

Explanation:

m±Delta m = 40g ± 0.4g

V±delta v = 10 cm ^3 ±1 cm ^3

P=m/v

P = 40 / 10 = 4g/cm^3

delta P=?

delta p/p = delta m/m + delta V / V

delta p / p = 0.4 / 40 + 1 /10

delta p = 0.11 X 0.4

= 0.44

Ans = 4± 0.4