a piece of metal of density 7.8×10³ weighs 20N. calculate the apparent weight of the metal when completely immersed in a liquid of density 8.3×10³
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Answer: 21.28 -20= 1.28N
Explanation:
W(liquid) = W(air)- Buyoant force
=20 - Vd2g; d2- density of liquid;
=20 - Vx8.3 x 10^3 x 10;
=20- (20 /7.3 x 10^3) x 8.3 x 10^3 =21.28-20N =1.28N
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