Question

a piece of metal of density 7.8×10³ weighs 20N. calculate the apparent weight of the metal when completely immersed in a liquid of density 8.3×10³

Answer 1

Answer: 21.28 -20= 1.28N

Explanation:

W(liquid) = W(air)- Buyoant force

            =20 - Vd2g; d2- density of liquid;

            =20 - Vx8.3 x 10^3 x 10;

             =20- (20 /7.3 x 10^3) x 8.3 x 10^3 =21.28-20N =1.28N