A piece of metal weighs 15.1 gm in air, 9.6 gm in water and 10.4 gm in liquid then the sp. gravity of the liquid is
Answers
Specific Gravity of the liquid is 0.85
Explanation:
Given:
Weight of the metal = 15.1 gram
Weight of metal in water = 9.6 gram
Weight of metal in liquid = 10.4 gram
To find out:
Specific gravity of the liquid
Solution:
Let the density of the metal be d
Then
Volume of the metal = Weight/Density = 15.1/d
When immersed in water, the metal will displace this volume of water
If density of water is dw
Then
Weight of water displaced = (15.1/d)dw
Therefore,
Weight of metal in water
= Weight of metal - Weight of water displaced
= 15.1 - (15.1/d)dw
According to the question
15.1 - (15.1/d)dw = 9.6
or, (15.1/d)dw = 5.5 ........... (1)
Similarly,
If the density of the liquid is dl
Then
Weight of metal in liquid
= Weight of metal - Weight of liquid displaced
= 15.1 - (15.1/d)dl
According to the question
15.1 - (15.1/d)dl = 10.4
or, (15.1/d)dl = 4.7 .................(2)
We have to find the specific gravity of the liquid i.e. dl/dw
Dividing eq (2) by eq (1)
dl/dw = 4.7/5.5 = 0.85
Therefore,
Specific gravity of the liquid is 0.85
Hope this answer is helpful.
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