Chemistry, asked by aishuclp, 1 month ago

A piece of metal weighs 40 g in air. When immersed in a liquid of specific gravity 2.0 at 28° C it weighs 32g. When the temperature of the liquid is raised to 32° C the metal pipe weighs 28 gm.If the specific gravity of liquid at 32° C is 1.5,then the linear expansion of the metal will be
1)1/48
2)1/12
3)1/32
4)1/16​

Answers

Answered by ayushmehral2208
0

Explanation:

Correct option is

A

2.23×10

−5

/

0

C

For 27

o

C , Loss in weight of the metal = weight of liquid displaced =46−30=16gm

Volume of metal at 27

o

C is V

1

=

1.24

16

=12.903cm

3

similarly , volume of metal at 42

o

C is V

1

=

1.20

46−30.5

=12.917cm

3

Volume expansion coefficient of the metal is γ=

V

1

2

−θ

1

)

V

2

−V

1

=

12.903(42−27)

12.927−12.903

=7.23×10

−5

/

o

C

The coefficient of linear expansion of metal is α=

3

γ

=2.4×10

−5

/

o

C

Similar questions