Question

a piece of metal weighs 50.0N in air,36.0N in water and 41.0N in oil.find the relative densities of metal and oil

Answer 1

Relative density of metal to the water = 1.3  , Relative density of oil to the water = 0.4  and Relative density of metal to oil = 5.5

Explanation:

Metals weighs in air = 50 N

Metals weighs in water = 36 N

Metals weighs in oil = 41 N

Metals weighs in water = 36 N = vρg

v = 36 / 10000 v

  = 0.0036 m^3

Therefore, the density of the metal will be (using the weight in air)

vρg = mg = 5 × 10

0.0036 × ρ = 5

ρ = 1388 kg/m^3

As the metal object weighs 41 N in oil,

We can write:  

mg − vρoilg = 41

− vρoilg = 41 - 50

− vρoil  = -9 / 10

  ρoil  = 9 / 10 x 0.0036

  ρoil=250 kg/m^3

• Relative density of metal to the water = 1.3
• Relative density of oil to the water = 0.4
• Relative density of metal to oil =5.5

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