Question

a piece of metal weighs 9.25 g 8n air 8.20 in water and 8.36 when immersed in gasoline what is the density of the metal
1. 8.20 g / cm3
2. 9.25 g / cm3
3. 8.81 g / cm3
4. 8.36 g / cm3​

Answer 1

Answer:

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Explanation:

When immersed in water, the metal object displaces (9.25 – 8.20) g = 1.05 g of water whose volume is (1.05 g) / (1.00 g cm–3) = 1.05 cm3. The density of the metal is thus (9.25 g) / (1.05 cm3) = 8.81 g cm–3.

The metal object displaces (9.25 - 8.36) g = 0.89 g of gasoline, whose density must therefore be (0.89 g) / (1.05 cm3) = 0.85 g cm–3.

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Answer 2

Answer:

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