Question

a piece of metal weighs 9.25 g 8n air 8.20 in water and 8.36 when immersed in gasoline what is the density of the metal
1. 8.20 g / cm3
2. 9.25 g / cm3
3. 8.81 g / cm3
4. 8.36 g / cm3​

Answer 1

Answer:

The density of the metal is thus (9.25 g) / (1.05 cm3) = 8.81 g cm–3. The metal object displaces (9.25 - 8.36) g = 0.89 g of gasoline, whose density must therefore be (0.89 g) / (1.05 cm3) = 0.85 g cm–3

the metal object displaced (9.25) - 8.36) g = 0.89g of gasoline whose density Must therefore be (0.89 g ) / (1.05 cm 3) = 0.85 g cm -3

please mark BRAINLIST ANSWER

Answer 2

Answer:

My special person is my first following

Anything hot enough to continuously sublimate water before contact (drop a mini star in the ocean and the ocean will evaporate before any water touches it)

Any hydrophobic material / anything coated in a hydrophobic material. (water literally is repelled and stays away from the material, think oil + water. You can’t call something “wet” if no water ever touches it)

Anything smaller than a molecule of water that doesn’t react with water. (Hard to be “wet” - e.g. coated with water, when you’re smaller than a molecule of water)