Question

a piece of metal weighs 9.25 g in air, 8.20 g in water, and 8.36 g when immersed in gasoline. a)What is the density of the metal? b) What is the density of the gasoline?

Answer 1

The density of the gasoline is 0.85 g cm^–3.

Explanation:

• When immersed in water, the metal object displaces (9.25 – 8.20) g = 1.05 g of water.
• Whose volume is (1.05 g) / (1.00 g cm–3) = 1.05 cm^3.
• The density of the metal is thus (9.25 g) / (1.05 cm^3) = 8.81 g cm^–3.

( b) The metal object displaces (9.25 - 8.36) g = 0.89 g of gasoline, whose density must therefore be (0.89 g) / (1.05 cm^3) = 0.85 g cm^–3.

Thus the density of the gasoline is 0.85 g cm^–3.

Also learn more

A body of mass 70 kg when completely immersed in water difference is 20,000 cm cube of water. Find the weight of a body in water and the relative density of material of body. ?

https://brainly.in/question/3302832

Answer 2

Answer:

I uploaded files for this answer