Question

A piece of method of density 7.8×10³ kg weigh 20N in
air.calculate the apparent weight of the metal when completely emesed in a liquid of density 8.3×10³ kg-³

Answer 1

Answer:

Explanation:

Apparent weight = V( d1 - d2)g ; d1 = 8.3 x 10^3 kg/m3;

d2= 7.8 x 10^3 kg/ m3;

   V(8.3 x 10^3 - 7.8 x 10^3)g = app weight;

V (0.5 x 10^3)g =app weight; => (0.5x 10^3 )/ 7.8 x 10^3  =5 /78;

5 /78 x 20 = 0.32N