Question

A piece of Mg is dissolved in 40 ml of 0.1N HCl completely. The excess of acid was neutralized by 15 ml of 0.2N NaOH.The weight of Mg is.

Answer 1

Answer:

me of HCl = 40 x 0.1 = 4 Excess me of acid = 15 x 0.2 = 3 Therefore me of acid that dissolved Mg = me of Mg dissolved = 4-3 = 1 me = .001 eq of Mg = 0.012 g of Mg

Explanation:

Answer 2

Answer:

The excess of acid was neutralized by 15 ml of 0.2N NaOH.The weight of Mg is. 2.