Chemistry, asked by keshavmpsjaipur, 9 months ago

A piece of Mg is dissolved in 40 ml of 0.1N HCl completely. The excess of acid was neutralized by 15 ml of 0.2N NaOH.The weight of Mg is.

Answers

Answered by Anonymous
0

Answer:

me of HCl = 40 x 0.1 = 4 Excess me of acid = 15 x 0.2 = 3 Therefore me of acid that dissolved Mg = me of Mg dissolved = 4-3 = 1 me = .001 eq of Mg = 0.012 g of Mg

Explanation:

Answered by prashant247
1

Answer:

The excess of acid was neutralized by 15 ml of 0.2N NaOH.The weight of Mg is. 2.

Similar questions