a piece of nichrome wire of resistance R is cut into four equals parts. These parts are then combined in parallel. If R' is thw equivalent resiatance of the parallel combination then the ratio R/R'will be?
please show the calculation
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Answered by
4
Answer:
cut resistance is=1/4 ,1/4 ,1/4,1/4
when connected in parallel
then resistance.=1/1/4+1/1/4+1/1/4+1/1/4= 4+4+4+4=16 ohm and original resistance is 1 ohm so
r/r,= 1/16 SO 1:16
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Answered by
6
Answer:
R : R' = 16 : 1
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Explanation:
Given,
Resistance: R ohm
According to question, the wire is cut into 4 equal parts hence the resistance of each part becomes:
=> R/4 ohm (use formula or R=ρL/A)
These wires are connected in parallel. Hence,
=> 1/R' = 4/R + 4/R + 4/R + 4/R
=> 1/R' = 16/R
=> R/R' = 16
=> R : R' = 16 : 1
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