Question

A piece of of silver weights 22 grams in air, 20.4 grams in alchol and 20.2 grams in water. Find the specific gravity of alchol?

Answer 1

Answer:

1.33

Explanation:

Specific gravity of the alcohol = 1.33

Step-by-step explanation:

Apply the principle of buoyancy.

(Actual mass of the object in air)-(Apparent mass of the object in water) = (Density of water) ×(Volume of water displaced)

22 - 20.2 = 1× V

Hence volume of water displaced = Volume of the object = 1.8 mL

Now, apply the same principle in the alcohol.

22 - 20.4 = d×1.8

Density of the liquid = 2.4÷1.8 = 1.33 g/ml

So, specific gravity of the alcohol = 1.33