Question

.A piece of platinum wire has resistance of 2.52
0°C. If its temperature coefficient of resistance
is 4 x 10-3/°C. Find the resistance of the wire at
80°C.​

Answer 1

Answer:

Here,s the answer :

Explanation:

We know,

R = Re (1+a(T-Te))

where, Re is the resistance of a conductor at a reference temperature of Te

and a=temperature coefficient of resistance so,

Re = 2.52

Te = 0

T = 80

a =  4 * 10^3

so, R = 2.52(1 + 4000*80)

        = 2.52 * 320001

        = 806402.52