Question

A piece of plywood measures 2¹/5m by 1¹/5m. Another piece of plywood measures 3¹/5m by 2²/5m. Both the pieces are cut into 10 equal pieces. 5 pieces of first plywood and 3 pieces of second plywood are joined together to make a one piece. What is the area of this piece of plywood? ​

Answer 1

Answer:

$hola \: mate \geqslant \leqslant$

Given,

Dimensions of first plywood = 2/5m × 1/5m

Dimensions of second plywood = 3/5m × 4/5m

=} Area of first ply wood = 2/25 sq. m

Area of second ply wood = 12/25 sq. m

ATP,

First ply wood is divided into 10 equal pieces

=} Area of 1 piece =

$\frac{ \frac{2}{25} }{10} sq.m$

$\frac{1}{25 \times 5}$

$\frac{1}{125} sq.m$

For second ply wood,

Area of one piece =

$\frac{ \frac{12}{25} }{10} sq.m$

$\frac{6}{25 \times 5}$

$\frac{6}{125} sq.m$

Area of joined ply wood =

$(\frac{1}{125} \times 5) + ( \frac{6}{125} \times 3)$

$\frac{(5 + 18)}{125}$

$\frac{23}{125}sq.m$

Therefore, Area of joined plywood

$= \frac{23}{125} sq.m$

Answer 2

Answer:

Given,

Dimensions of first plywood = 2/5m × 1/5m

Dimensions of second plywood = 3/5m × 4/5m

=} Area of first ply wood = 2/25 sq. m

Area of second ply wood = 12/25 sq. m

ATP,

First ply wood is divided into 10 equal pieces

=} Area of 1 piece =

\frac{ \frac{2}{25} }{10} sq.m

10

25

2

sq.m

\frac{1}{25 \times 5}

25×5

1

\frac{1}{125} sq.m

125

1

sq.m

For second ply wood,

Area of one piece =

\frac{ \frac{12}{25} }{10} sq.m

10

25

12

sq.m

\frac{6}{25 \times 5}

25×5

6

\frac{6}{125} sq.m

125

6

sq.m

Area of joined ply wood =

(\frac{1}{125} \times 5) + ( \frac{6}{125} \times 3)(

125

1

×5)+(

125

6

×3)

\frac{(5 + 18)}{125}

125

(5+18)

=23/125