Question

A piece of rock salt weighs 108.2g in air and 48.2g in saturated brine of relative density 1.2. What is the relative density of rock salt?

Answer 1

Buoyant force= 108.2-48.2
= 60 g wt
Density of liq ×Volume × acc. due to gravity=60 g wt
1.2×volume = 60 g
Volume= 50 g/cm3
Mass=108.2 g
Density= mass/ volume
=2.164 g/cm3
Relative density=2.164

Answer 2

Answer:

Explanation:

Solution :-

Loss of water in brine = (108.2 - 48.2) g.wt

= Weight of brine displaced

R.D. of brine

R.D. of brine = weight of certain volume of brine/weight of an equal volume of water

1.2 = 60.2/weight of an equal volume of water

Weight of an equal volume of water = 60.2/1.2

Weight of an equal volume of water = 50 g. wt

Therefore, specific gravity of rock salt

Specific gravity of rock salt = weight of salt in air/weight of an equal volume of water

Specific gravity of rock salt = 108.2/50

Specific gravity of rock salt = 2.16

Hence, the relative density of rock salt is 2.16.