Question

A piece of rope is 7m 20cm long. It is cut into 2 pieces. One piece is shorter than the other by 1m 80cm. Find the length of the shorter piece.​

Answer 1

Step-by-step explanation:

Here,

let the cut pieces be x(shorter) and x+1m80cm(longer rope)

We have,

x+(x+1m80cm) = 7m20cm

2x= 7m20cm-1m80cm

x= 5m40cm/2 = 2m70cm

Answer 2

$\huge\purple{\underline{\underline{Question:}}}$

A piece of rope is 7m 20cm long. It is cut into 2 pieces. One piece is shorter than the other by 1m 80cm. Find the length of the shorter piece.

$\huge\purple{\underline{\underline{Answer:}}}$

$\bf\underline{Given:}$

A piece of rope is 7m20cm= 720 cm long

Cut into 2 pieces

$\bf\underline{Solution:}$

Let longer piece be x.

Shorter piece = $x-1m 80cm=> x - 180cm$

x + x - 180cm = 720

=> $2x - 180 cm$ = 720

=> $2x$ = 720+180

=> $2x$ = 900

=> $x = \frac{900}{2}$

=> $x = 450 cm$

$x - 180cm= 450-180$

=> $270 cm$

=> $2m\:70 cm$ Ans.

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