Question

a piece of silver weighs 66gf in air and 55 of in water find relative density of silver

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Answer 1

Explanation:

1 gf = 0.0098 N

66 gf = 0.6468 N

55 gf = 0.539 N

$relative \: density = \frac{wt. \: in \: air}{wt. \: in \: air - wt. \: in \: water}$

$= \frac{0.6468}{0.6468 - 0.539} = \frac{0.6468}{0.1078} = 6$

Therefore , the relative density of silver is 6.

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