Question

A piece of silver weight 22g in air, 20.4g in alcohol and 20.2g in water. Find the specific gravity of alcohol?

Answer 1

Answer:

Specific gravity of the alcohol = 1.33

Step-by-step explanation:

Apply the principle of buoyancy.

(Actual mass of the object in air)-(Apparent mass of the object in water) = (Density of water) ×(Volume of water displaced)

22 - 20.2 = 1× V

Hence volume of water displaced = Volume of the object = 1.8 mL

Now, apply the same principle in the alcohol.

22 - 20.4 = d×1.8

Density of the liquid = 2.4÷1.8 = 1.33 g/ml

So, specific gravity of the alcohol = 1.33

Answer 2

Answer:0.8889

Step-by-step explanation:

Weight of silver in air=22 gram

Weight of silver in alcohol=20.4gram

Weight of silver in water=20.2 gram

Weight loss of silver in water=22-20.2=1.8g

Weightloss of silver in alcohol=22-20.4=1.6g

Relative density of alcohol=

Loss of weight in alcohol÷Loss of weight

In water

Relative density of alcohol =1.6÷1.8

=0.8889